Tuple5FromExpr
Default implementation of FromExpr[Tuple5[...]]
- Transform '{Tuple5(x1, ..., x5)} into Some(Tuple5(x1, ..., x5)) if all xi can be transformed using FromExpr[Ti]
- Otherwise returns None
- Source:
- FromExpr.scala
Default implementation of FromExpr[Tuple5[...]]
- Transform '{Tuple5(x1, ..., x5)} into Some(Tuple5(x1, ..., x5)) if all xi can be transformed using FromExpr[Ti]
- Otherwise returns None