MapFromExpr
given MapFromExpr[T, U](using val x$1: Type[T], val x$2: Type[U], val x$3: FromExpr[T], val x$4: FromExpr[U]): FromExpr[Map[T, U]]
Default implementation of FromExpr[Map]
- Transform '{Map(x1, ..., xn)} into Some(Map(x1, ..., xn)) if all xi can be transformed using FromExpr[Ti]
- Transform '{Map.empty} into Some(Map())
- Otherwise returns None
- Source
- FromExpr.scala